最近遇到几个文件,使用的图像编码是BGR565格式。所用包为PIL,python3以上似乎不支持了,可以用另一个pillow代替,大神魔改的版本。功能一样
BGR与RGB相近,无非就是将B与R的二进制调换位置,565格式代表共16位数据。
首先将文件二进制数据读取,并保存为txt文档。然后使用py编写程序进行数据解析。
from PIL import Image, ImageDraw w = 236 # 宽 h = 155 # 高 FileAdd = "D:\\1.txt" # 用于转换的 HEX = {} HEX1 = {} RGB = [] def Hex_To_Dec(hex): if hex == '0': rx = 0 elif hex == '1': rx = 1 elif hex == '2': rx = 2 elif hex == '3': rx = 3 elif hex == '4': rx = 4 elif hex == '5': rx = 5 elif hex == '6': rx = 6 elif hex == '7': rx = 7 elif hex == '8': rx = 8 elif hex == '9': rx = 9 elif hex == 'A': rx = 10 elif hex == 'B': rx = 11 elif hex == 'C': rx = 12 elif hex == 'D': rx = 13 elif hex == 'E': rx = 14 elif hex == 'F': rx = 15 else: return (100) return (re) # main() if __name__ == "__main__": f = open(FileAdd, encoding="utf-8") # 打开文件 print("正在解析" + FileAdd + "的数据,合成文件名为" + str(w) + "*" + str(h) + "的图片") x = 0 z = 0 for x in range(w * h * 60): # 进制转换 16-10 f.seek(z + 0, 0) f1 = f.read(1) f.seek(z + 1, 0) f2 = f.read(1) f.seek(z + 3, 0) f3 = f.read(1) f.seek(z + 4, 0) f4 = f.read(1) z = z + 6 HEX1[x] = ((Hex_To_Dec(f1) << 12) + (Hex_To_Dec(f2) << 8) + (Hex_To_Dec(f3) << 4) + Hex_To_Dec(f4)) a = bin(HEX1[x]) #BRG与RGB互相转换 a1 = a[2:7] a2 = a[7:13] a3 = a[13:18] c = a3 + a2 + a1 HEX[x] = int(c,2) if z >= (w * h * 6): break f.close() # 关闭文件 x = 0 for x in range(len(HEX)): r = (((HEX[x] & 0xF800) >> 8)) g = (((HEX[x] & 0x7E0) >> 3)) b = (((HEX[x] & 0x1F) << 3)) rgb = (r, g, b) RGB.append(rgb) # print(RGB) # print(HEX) image = Image.new('RGB', (w, h), (255, 255, 255)) # 创建新图片对象 draw = ImageDraw.Draw(image) # 创建Draw对象用于绘制新图: x = 0 y = 0 i = 0 for y in range(h): # 填充每个像素并对对应像素填上RGB值: for x in range(w): draw.point((x, y), fill=RGB[i]) i = i + 1 image.save('D:\\2.jpeg', 'jpeg') # 将转换后的图像保存到D盘中 image.show() # 查看图像
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admin:支持一下,感谢分享!,+10,